Find the three consecutive odd numbers whose sum is 987.
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Answer:
327, 329,331
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To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 987
3X + 3 = 987
3X + 3 - 3 = 987 - 3
3X = 984
3X/3 = 984/3
X = 328
Which means that the first number is 328, the second number is 328 + 1 and the third number is 328 + 2. Therefore, three consecutive integers that add up to 987 are 328, 329, and 330.
328 + 329 + 330 = 987
We know our answer is correct because 328 + 329 + 330 equals 987 as displayed above.
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