Question

Find the three consecutive odd numbers whose sum is 987.​

Answer 1

Answer:

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 987

3X + 3 = 987

3X + 3 - 3 = 987 - 3

3X = 984

3X/3 = 984/3

X = 328

Which means that the first number is 328, the second number is 328 + 1 and the third number is 328 + 2. Therefore, three consecutive integers that add up to 987 are 328, 329, and 330.

328 + 329 + 330 = 987

We know our answer is correct because 328 + 329 + 330 equals 987 as displayed above.

Answer 2

Answer:

$\huge{\underline{\textsf{\textbf{~~~Answer}}}}$

let the number be n , n+2 and n+4

the sum of numbers is 987

so ,

n + n + 2 + n + 4 = 987

= 3n + 6 = 987

= 3n = 987 - 6

= 3n = 981

= n = $\frac{981}{3}$

= n = 327

similarly , n + 2 = 327 + 2 = 329

n + 4 = 327 + 4 = 331

therefore , the required odd numbers are 327 , 329 and 331