Question

Find the three consecutive odd numbers whose sum is 987.​

Answer 1

Answer:

The numbers are 327, 329 and 331.

Step-by-step explanation:

Let the numbers be :

x

x + 2

x + 4

⟶ x + (x + 2) + (x + 4) = 987

⟶ 3x + 6 = 987

⟶ 3x = 987 - 6

⟶ 3x = 981

⟶ x = 981/3

⟶ x = 327

Other numbers :

⟶ (x + 2) = (327 + 2) = 329

⟶ (x + 4) = (327 + 4) = 331

Therefore, the numbers are 327, 329 and 331.

Answer 2

The numbers are 327, 329 and 331.

Step-by-step explanation:

Let the numbers be :

• x
• x + 2
• x + 4

$\longrightarrow x + (x + 2) + (x + 4) = 987$

$⟶ 3x + 6 = 987$

$⟶ 3x = 987 - 6$

$⟶ 3x = 981$

$⟶ x = 981/3$

$⟶ x = 327$

Other numbers :

$⟶ (x + 2) = (327 + 2) = 329$

$⟶ (x + 4) = (327 + 4) = 331$

Therefore, the numbers are 327, 329 and 331.