Question

find the three consecutive odd numbers whose sum is 987​

Answer 1

solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 987

3X + 3 = 987

3X + 3 - 3 = 987 - 3

3X = 984

3X/3 = 984/3

X = 328

Which means that the first number is 328, the second number is 328 + 1 and the third number is 328 + 2. Therefore, three consecutive integers that add up to 987 are 328, 329, and 330.

328 + 329 + 330 = 987

We know our answer is correct because 328 + 329 + 330 equals 987 as displayed above.

Answer 2

Step-by-step explanation:

let the numbers be a, a+2, a+4 given,

a+(a+2)+(a+4)=987

ata+2+a+4=987

3a+6=987

3(a+2)=987

a+2=987/3

a+2=329

a=329-2

a=327

so,

the numbers are 327, 329 & 331