Question

Find the three consecutive terms in an A.P Whose sum is 18 and the sum of their squares is 140​

Answer 1

(a -d)³*a³ * (a+d) ³ =3375

Step-by-step explanation:

let the three consecutive terms are =A.p (a-d) a and (a+d)

so the some of the three consecutive terms are (a-d) +a+ ( a -d)

but here the sum of the three consecutive terms is given =9

= a =9/3=3

= (a-d) ³*(a+d) ³=3375