Question

Find the three consecutive terms in an ap whose sum is 6 and product is 120

Answer 1

a-d,a,a+d be the three consecutive terms

then,

a-d+a+a+d=6

3a=6

a=2

also putting value of a

(a-d)(a)(a+d)=120

2-d)(2+d)=120\2

4-dsqaure=60

solve further and get the answer