Question

find the three consecutive terms of an A.P. whose sum is 45 and their product is 3240 .....(ans is 18 15 12 or 12 15 18)

Answer 1

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thank you

Answer 2

Hey

Here is your answer,

Let the three consecutive integers be a -d , a and a+d.

a-d+a+a+d = 45
3a = 45
a = 45/3
a = 15

Now the numbers are (15-d) , 15 and (15+d)

(15-d) x 15 x (15+d) = 3240
(15-d) x (15+d) = 3240/15
(15)^2 - (d)^2 = 216
-d^2 = 216 - 225
d^2 = 9
d = +/-3

If d= +3, The terms are
a-d = 15-3=12
a=15
a+d = 15+3=18

If d=-3 , the terms are
a-d = 15+3=18
a=15
a+d=15-3=12

Hope it helps you!