Question

find the three consecutive terms which are in AP whose sum is 24 and product is 440

Answer 1

a-d, a, a+d

a - d + a + a + d = 24

3a = 24

a = 8

(a-d) a (a + d) = 440

a x (a² - d²) = 440

64 - d² = 440/8 = 55

d² = 64 - 55 = 9

d = 3

so numbers 5, 8, 11