find the three integers in AP such that their sum is 27 and their product is 504
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Step-by-step explanation:
Let the numbers be a-d,a,a+d
As per the problem,
a-d+a+a+d=27
3a=27
a=9
And, (a-d)(a)(a+d)=504
(a*a-d*d)=56
81-d*d=56
d*d=81-56
d*d=25
d=5
Therefore,the numbers are (9-5),(9),(9+5)
=4,9,14.
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