Question

find the three no in AP if the sum of these no is -3 and their product is 8​

Answer 1

Answer:

a-d=-10,a=-1,a+d=8

Step-by-step explanation:

Let the three terms be a-d, a, a+d

$a - d + a + a + d = - 3 \\ 3a = - 3 \\ a = - 1$

$( a - d)(a)(a + d) = 8 \\ {a}^{2} - {d}^{2} (a) = 8 \\ {a}^{3} - ad = 8 \\ { - 1}^{3} - ( - 1)d = 8 \\ - 1 + d = 8 \\ d = 9$

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Answer 2

Answer:

in A.P these are numbers a-d, a, a+d.

their sum is -3

(a+d)(a)(a-d)=-3

=3a=-3

a=-1

their product =8

(a+d)(a)(a-d)=8

a cube- d square a=8

d square =9

d=+ or -3

if d=-3,a=-1

(a-d)(a)(a+d)=-4,-1,2

d=3,a=-1

(a-d)(a)(a+d)=2,-1,-4

hope it helps u............