Question

find the three number in ap whose sum is 18 and product is 120​

Answer 1

Answer:

the numbers are

2,6 and 10

Step-by-step explanation:

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Answer 2

Answer:

2,6,10

Step-by-step explanation:

Let the 3 consecutive terms in the A.P. be a−d,a,a+d

Thus a−d+a+a+d=18 and also (a−d)(a)(a+d)=120 Thus, solving these two equations we get 3a=18 or a=6

Thus putting the value of a=6 in the second equation, we get

(6²-d²)6=120

36-d²=20

d²=16

Or d=±4

Thus the three consecutive terms in the A.P. are 2,6,10