Question

find the three numbers if the sum of three consecutive terms is on AP is -6 and the product is 90.find the three numbers​

Answer 1

Step-by-step explanation:

let the three consecutive terms be a-d, a, a+d

given,

a-d+a+a+d=(-6)

3a=(-6)

a=-6/3=-2

product of three number is 90

so

a-d * a * a +d= 90

a(a2-d2) = 90

-2(4-d2) =90

-8+d2= 90

2d2=98

d2=98/2

d=√49

d=7

three numbers are

a-d=-2-7=-9

a=-2

a+d=-2+7=5