find the three numbers
in
A.p such that
their sum is 24 and sum of their square is
200
Answers
Answered by
1
Step-by-step explanation:
Answer. = 224= (8-d)²+8²+(8+d)²=224= 2(64+d²)= 224-64=160=64+d=80=> d² = 16, d = ±4.
or
u can use this method
let the 3 numbers be
a−d,a,a+d
Sum =24
if 3a=24
a=8
∴ the numbers are
(8−d),8,(8+d)
Sum of squares a=200
⇒(8−d)
2
+8
2
+(8+d
2
)=200
⇒3(8
2
)+2d
2
=200
⇒2d
2
=8⇒d
2
=4⇒d=2
∴ The 3 numbers are (8−2),8,(8+2)
⇒6,8,10
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