Question

Find the three numbers in AP such that their sum is 12 and the sum of their product is 408

Answer 1

Answer:

Step-by-step explanation:

Let the terms be, a, a+d, a+2d. Given that sum is 12.

That is, a+(a+d)+(a+2d) = 12

That is, 3a+3d = 12,

Meaning, a+d=4

Since sum is 12, numbers can be (1,4,7) or (2,4,6) or (3,4,5).

But it's given that sum of cubes is 408.

This is satisfied only by (1,4,7).