Question

find the three numbers in the ratio 2 ratio 3 ratio 5 such that the sum of their square is 608 ​

Answer 1

Step-by-step explanation:

Let the numbers be 2x,3x,5x

According to statement,

2x^2+3x^2+4x^2=608

4x^2+9x^2+25x^2=608

38x^2=608

x^2=608÷38

x^2=16

x=4

Hence,numbers are

2x=2×4=8

3x=3×4=12

4x=5×4=20

Hope this may help you

Answer 2

Answer:

4k2+9k2 +25k2=608

38k2=608

k2=608/38

k2=16

(taking square root)

k=4

numbers are

2k=2×4=8

3k=3×4=12

5k=5×4=20

8,12,20 are the numbers

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