Find the three numbers of G.P such that the respective sum and product are 6 and -64
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Step-by-step explanation:
Let the three numbers be a/r,a,ar
⇒a/r×a×ar=1000
⇒a3=1000
⇒a=10
2(a+6)=(ar+7)+a/r where a=10
⇒32r=10r 2+7r+10
⇒10r2+7r−32r+10=0
⇒10r2−25r+10=0
⇒2r2−5r+2=0
⇒2r2−4r−r+2=0
⇒2r(r−2)−1(r−2)=0
⇒(r−2)(2r−1)=0
⇒r=2 1/2
∴a=10,r=2⇒ terms are
10/2,10,10×2 or 5,10,20
∴a=10,r=1/2⇒ terms are 10/1/2 ,10,10×1/2or 20,10,5
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