Question

Find the three numbers such that the second is twice the first, the third is three times the first and their sum is 180

Answer 1

Let the numbers be a,b and c
b=2a and c=3a

a+b+c=180
a+2a+3a=180
6a=180
a=180/6=30

therefore the three numbers are,
a=30, b=60 and c=90

Answer 2

Answer:

Let the number be x,y,and z

y=2x z=3x

According to Question

x+y+z=180

x+2x+3x=180

6x=180

x=180/6

x=30

x=30

y=2×30=60

z=3×30=90