Question

find the three numbers whose HCF is 12 . If they are in the ratio 1:2:3

Answer 1

Hi there !!

Let the required numbers be x, 2x, 3x.
As 1 , 2 and 3 are co prime numbers that do not have common factor between them other than 1 ;

H.C.F = x = 12


The numbers are :
x = 12
2x = 2 x 12 = 24
3x = 3 x 12 = 36

Hence : 12 , 24 , 36 are the numbers .....

Answer 2

let the number be any variable like y
1y,2y,3y and the hcf=12
the first number wil be 12
and second will be 2*12= 24
third will be3*12 =36...
hope it will help u