find the three positive numbers in the ratio 1:4:2 such that the sum of their squares is equal to 1701
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Answer:
The numbers are in the ratio of 1:4:2.
Let the numbers be a, b and c.
So, a = 1x, b = 4x, c = 2x.
So according to the question,
a²+b²+c² = 1701
(1x)² + (4x)² + (2x)² = 1701
On solving the above equation we get,
x = +9 or x=-9.
But since we want positive numbers we will take x=+9.
Hence, a = 9, b = 36, c = 18.
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