Question

Find the three prime numbers such that product of the first two is 1147 and the product of the last two
numbers is 1517?

Answer 1

Step-by-step explanation:

Let the 3 prime numbers be a,b,c

Given numerous 1147 & 1517 are prime numbers with no other multiples other than 1 and itself

hence the numbers a,b,c are

1147,1,1517

Product of 1st two prime numbers = 1147×1 = 1147

Product of last two prime numbers = 1×1517 = 1517

Hence a = 1147 , b = 1 , c = 1517

Answer 2

Step-by-step explanation:

let a b and c be the three prime numbers

according to the given questions

a×b = 1147

a×b= 31×37

and

b×c = 1517

b×c = 37×41

therefore the three prime numbers are 31 ,37 and 41