Question

Find the three real zeros of trinomial p(x) = x³ - x​

Answer 1

Step-by-step explanation:

Given that P(x)=x^3-x

zeros of P(x) are x^3-x=0

=> x(x^2-1)=0

=> x=0 and x^2-1=0

=> x=0 and x^2=1

=> x=0 and x= + or - √1

therefore x= -1,0,+1 are real zeros of function P(x)=x^3-x