Find the three solutions of the equation 4×+3y =12
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We find solution by putting the value of X in equation
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umaleanurag111:
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if x=0 then if x=1 then if x=2 then
4*0 + 3y =12 4*1 +3y = 12 4*2 +3y=12
3y = 12 4 + 3y =12 8+3y=12
y =12/3 3y = 8 3y =4
y= 4 y =3/8 y =4/3
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