Question

Find the three terms in AP such that their sum is 3 and product is -8.

Answer 1

Explanation:

Let the 3 terms be a-d, a and a+d

ATQ,

(a-d) +a+(a+d) = 3

=> a-d+a+a-d =3

=> 3a = 3

Therefore

a = 1

Now

(1-d)*(1)*(1+d)= - 8

=> ( 1-d) *(1+d) = - 8

=> 1² - d² = - 8

=> - d² = - 9

=> d² = 9

=> d =3 or - 3

Therefore the three terms are

1-3,1and 1+3

= - 2, 1 and 4

Or

1-(-3),1 and 1+(-3)

= 4,1,-2

Hope it helps you :)