Physics, asked by sivamanoj15, 8 hours ago

find the thrust required to exert of pressure of 50000 Pascal's on an area of 0.05 m²
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Answers

Answered by Anonymous
128

Understanding the concept:

•We are given in the question that pressure exert to thrust required is 50000 Pascal and area required is 0.05\sf{m}^{2} and we are said to find what force act on thrust so first of all as we know the formula of force is equal to pressure is multiple of area so we are provided with formula then we will put the values which are given and then find the force acts on thrust so let's find!

Given:-

•Pressure exerts on thrust = 50000Pascal

•Area on thrust = 0.05\sf{m}^{2}

To Find:-

•Force act on thrust = ?

Solution:-

Given,

  • Pressure = 50000 Pascal
  • Area = 0.05\sf{m}^{2}

As we know,

\:\:\:\:\large{\sf{\underline{\boxed{\purple{Force = Pressure × Area}}}}}

Now put the values

 \:   \sf \implies \: force = 50000 \times 0.05  \\  \\  \:   \sf \implies \: force = 2500 \: newton

 \:  \sf   \therefore hence \: force \: act \: on \: thrust \: is \: 2500 \: newton

Additional Information:-

  • Pressure = \sf{\dfrac{Force}{Area}}
  • Area = \sf{\dfrac{Force}{Pressure}}

___________________________

Answered by Anonymous
0

Answer:

Understanding the concept:

•We are given in the question that pressure exert to thrust required is 50000 Pascal and area required is 0.05\sf{m}^{2}m

2

and we are said to find what force act on thrust so first of all as we know the formula of force is equal to pressure is multiple of area so we are provided with formula then we will put the values which are given and then find the force acts on thrust so let's find!

Given:-

•Pressure exerts on thrust = 50000Pascal

•Area on thrust = 0.05\sf{m}^{2}m

2

To Find:-

•Force act on thrust = ?

Solution:-

Given,

Pressure = 50000 Pascal

Area = 0.05\sf{m}^{2}m

2

As we know,

\:\:\:\: \large{\sf{\underline{\boxed{\purple{Force = Pressure × Area}}}}}

Force=Pressure×Area

Now put the values

\begin{gathered} \: \sf \implies \: force = 50000 \times 0.05 \\ \\ \: \sf \implies \: force = 2500 \: newton\end{gathered}

⟹force=50000×0.05

⟹force=2500newton

\: \sf \therefore hence \: force \: act \: on \: thrust \: is \: 2500 \: newton∴henceforceactonthrustis2500newton

Additional Information:-

Pressure = \sf{\dfrac{Force}{Area}}

Area

Force

Area = \sf{\dfrac{Force}{Pressure}}

Pressure

Force

___________________________

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