Question

find the time in which rs 2000 eill ampunt to rs 2330 at 11 % p.a.

Answer 1

Principal (P) =₹2000

Amount (A) =₹2330

Rate of interest (R)=11%

Time(T)= T

Simple interest (S.I.) =( A-P)

                                 = ₹(2330-2000)

                                = ₹330

∴ T=(S.I.×100)/(P×R)

     = (330×100)/(2000×11)

      = (30/20)

      =(3/2)

      =1+1/2 years ( 1 whole of 1/2 years)

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