Find the time (in years) in which Rs. 12500 will produce Rs. 3246.40 as compound interest at 8% per annum , compounded annually
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Compound Interest Formula:
Given,
p= ₹12,500
a= p+i = ₹(12,500 + 3,246.40) = ₹15,746.49
r= 8% or 0.08 per annum
t= x years
1st year:
S.I:
8% of ₹12,500
=8/100 × 12,500
=8 × 125
=₹1,000
Therefore, 1st year a= ₹(12,500 + 1,000) = ₹13,500
2nd year:
C.I:
8% of ₹13,500
=8/100 × ₹13,500
=8 × 135
=₹1,080
Therefore, 2nd year a= ₹(13,500 + 1,080) = ₹14,580
3rd year:
C.I:
8% of ₹14,580
=8/100 × 14,580
=0.08 × 14,580
= ₹1,166.40
Therefore, 3rd year a= ₹(14,580 + 1,166.40) = ₹ 15,746.40
Total C.I. accumulated in a period of 3 years= ₹ (1,000 + 1,080 + 1,166.40) = ₹3,246.40
Answer- 3 years.
Given,
p= ₹12,500
a= p+i = ₹(12,500 + 3,246.40) = ₹15,746.49
r= 8% or 0.08 per annum
t= x years
1st year:
S.I:
8% of ₹12,500
=8/100 × 12,500
=8 × 125
=₹1,000
Therefore, 1st year a= ₹(12,500 + 1,000) = ₹13,500
2nd year:
C.I:
8% of ₹13,500
=8/100 × ₹13,500
=8 × 135
=₹1,080
Therefore, 2nd year a= ₹(13,500 + 1,080) = ₹14,580
3rd year:
C.I:
8% of ₹14,580
=8/100 × 14,580
=0.08 × 14,580
= ₹1,166.40
Therefore, 3rd year a= ₹(14,580 + 1,166.40) = ₹ 15,746.40
Total C.I. accumulated in a period of 3 years= ₹ (1,000 + 1,080 + 1,166.40) = ₹3,246.40
Answer- 3 years.
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