Question

Find the time it takes a ball falling from a tall building to double its speed from 9.0 m/s to 18 m/s

Answer 1

Heya !

Here's your answer !!

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Initial velocity ( u ) = 9 m/s

Final velocity ( v ) = 18 m/s

Acceleration due to gravity ( g )=10 m/s^2

Time ( t ) = ?

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We know,

g = $\frac{v - u }{t}$

10 = $\frac{ 18 - 9 }{t}$

t = 9/10

Time = 0.9 seconds ANS


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THANKS !!

Answer 2

As it is given in the question that,

A ball is falling from a tall building and its velocity is doubled from 9 m/s to 18 m/s. As we also know that when any body falls from any place then it is due to the action of Gravity of Earth.

Now,

Initial Velocity (v) = 9 m/s
Final Velocity (v') = 18 m/s
Acceleration due to Gravity (g) = 9.8 m/s^2

Again,

=> g = v'-v/t

=> 9.8 x t = (18-9) m/s

=> t = (9/9.8) s

=> t = 0.91 s



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