Question

find the time period for each of the following. (a) P= rupees 9540 I = rupees 1808 r = 8% p.a (b) P = rupees 6600 I= rupees 600 , r = 4% p.a​

Answer 1

$\sf \frak{ \purple{Answer:-}}$

(a) P= Rs.9540

I=Rs.1808

R= 8%

$\tt{T= \frac{ \cancel{1808} ^{ \cancel{ 226} ^{113} } \times 10 \cancel0}{ \cancel{954} ^{477} \cancel0 \times \cancel8} }$

$\tt{ = \frac{1130}{477} }$

$\tt{ = {\underline {\underline{ \red{2.36 \: years}}}}}$

(b) P=Rs.6600

I= Rs.600

R= 4%

$\tt{T = \frac{ {600 }\times 1 {00}}{ 66 00 \times 4} }$

$\tt{ = \frac{25}{11} }$

$\tt{ = \underline{ \underline{ \red{2.27 \: years}}}}$

Answer 2

(a) P= Rs.9540

I=Rs.1808

R= 8%

\tt{T= \frac{ \cancel{1808} ^{ \cancel{ 226} ^{113} } \times 10 \cancel0}{ \cancel{954} ^{477} \cancel0 \times \cancel8} }T=

954

477

0

×

8

1808

226

113

×10

0

\tt{ = \frac{1130}{477} }=

477

1130

\tt{ = {\underline {\underline{ \red{2.36 \: years}}}}}=

2.36years

(b) P=Rs.6600

I= Rs.600

R= 4%

\tt{T = \frac{ {600 }\times 1 {00}}{ 66 00 \times 4} }T=

6600×4

600×100

\tt{ = \frac{25}{11} }=

11

25

\tt{ = \underline{ \underline{ \red{2.27 \: years}}}}=

2.27years