Find the time period of a rod pendulum having mass m and length l
Answers
Answered by
0
or a rigid body oscillating about horizontal axis passing through the point O the time period is given by
T=2πImg(OG)−−−−−−−√T=2πImg(OG)
Where I moment of rigid body and OG is the distance of the point of pivot to the centre of gravity G and I is the moment of inertia of the rod.
I=13I=13me2me2
OG=l2OG=l2
T=2π13ml2mgl2−−−−−−⎷T=2π13ml2mgl2
=2π2l3g−−−√=2π2l3g
Answer : 2π
T=2πImg(OG)−−−−−−−√T=2πImg(OG)
Where I moment of rigid body and OG is the distance of the point of pivot to the centre of gravity G and I is the moment of inertia of the rod.
I=13I=13me2me2
OG=l2OG=l2
T=2π13ml2mgl2−−−−−−⎷T=2π13ml2mgl2
=2π2l3g−−−√=2π2l3g
Answer : 2π
Similar questions