Question

find the time period of a simple pendulum whose length is 2m.​

Answer 1

formula

↓↓↓↓

T = 2π√L÷g

put the value L = 2m

we get

T = 2π√2÷9.8

hope it's helpful to you

Answer 2

Time period t = 2$\pi$ $\sqrt{l/g}$

t = 2*3.14 $\sqrt{2/9.8}$

t = 6.28 * 0.447

t = 2.807 sec or 2.81 sec