Question

find the time period of simple pendulam length 0.9 mm and g=10 m/s​

Answer 1

Explanation:

I hope you understand

ok.

Answer 2

time period for simple pendulum is given as

T = 2π √l/g

T = 2×3.142 √ 0.9 × 10^-3/10

T = 6.284 √ 9× 10^-4

T = 6.284×√ 9×10^ -5

T = 6.284 × 3 × 10^-2 √ 0.1

T = 18.852 × 10^-2 × 0.3162

T = 5.961 × 10^-2 s

is the required answer