Find the time period of simple pendulum whose length is 88.2cm.the value of acceleration due to gravity is 9.8metre per second square at the place where experiments performed
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2*22/7*(√88.2/9.8) = 18.8 seconds
Answered by
1
Answer:
2π√l/g=18.8 sec
Explanation:
2(22/7)√88.2/9.8
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