Question

find the time period of the rotation of the earth if the acceleration due to gravity becomes half of the acceleration due to gravity on the surface of the earth​

Answer 1

Explanation:

For the weight to be zero at the equator, value of gravity should be zero. i.e

g

′

=g−R(ω

′

)

2

=0

⇒ω

′

=

R

g

=123.7×10

−5

s

−1

So, time period(T) is calculated using:

T=

ω

′

2π

=

123.7

2π

×10

5

s=5079.4 s=84.66 min

Mark as me a brainliest