Question

Find the time period.

p=₹ 6600, I =₹ 792, R=₹4% p.a.​

please solve this in notebokk​

Answer 1

T=SI*100/P*R
T=792*100/6600*4
T=3years

Answer 2

Answer :-

Given :-

• Principal = ₹ 6600
• Simple interest = ₹ 792
• Rate of interest = 4% p.a.

To Find :-

• Time period

Solution :-

We know that,

Simple interest = P × R × T / 100

Substituting the value in formula -

➩ 792 = 6600 × 4 × T / 100

➩ 792 = 66 × 4 × T

➩ 264 T = 792

➩ T = 792 / 264

➩ T = 3

Time period = 3 years