Question

Find the time required to earn rs 400 as a simple interest on the principal of rs 2000 at the rate of 10%.

Answer 1

$\mathfrak{\large{\underline{\underline{\red{Answer :-}}}}}$

In 2 years, Rs.2000 will yield Rs.400 as Simple Interest in 10% rate.

$\mathfrak{\large{\underline{\underline{\red{Explanation :-}}}}}$

$\textbf{Given :}$

Simple Interest = Rs. 400

Principal = Rs .2000

Rate of Interest = 10%

$\textbf{To find :}$

The time

$\textbf{Solution : }$

Here,

▣ Principal (P) = Rs. 2000

▣ Rate (R) = 10%

▣ Simple Interest (SI) = Rs. 400

Consider Time as T

$\boxed{\tt{SI = \frac{Principal \times Rate \times Time}{100}}}$

${\tt{\implies} \: 400 = \dfrac{2000\times 10 \times T}{100}}$

${\tt{\implies} \: 400 = \dfrac{20000\times T}{100}}$

${\tt{\implies} \: 400 \times 100= 20000\times T}$

${\tt{\implies} \: 40000= 20000\times T}$

${\tt{\implies} \:T = \dfrac{40000}{20000}}$

${\tt{\implies} \:T = 2}$

Time = 2 years

$\therefore$ In 2 years, Rs.2000 will yield Rs.400 as Simple Interest in 10% rate.

Answer 2

SI = P × R × T/100

400 = 2000 × 10 × T /100

T = 400 × 100/2000 × 10

T = 40000/20000

T = 2

The time is 2 years !!

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