Question

Find the time (T), when
a) P = 1,000, R = 5% p.a., SI = 110​

Answer 1

Answer:

$\frac{11}{5}$

$\frac{p \times r \times t}{100} = si$

Answer 2

Time = 2.2 years

Explanation :-

Given :-

• Principal (P) = Rs. 1000
• Rate of interest (R) = 5%
• Simple interest (SI) = Rs. 110

To Find :-

• Time (T) = ?

Solution :-

As we know that,

$\dag \: { \boxed{ \rm{ \red{ \underline{S.I = \frac{P \times \: R \times \: T }{100} }}}}}$

[ Putting values ]

$\implies \rm \: 110 = \frac{1000 \times 5 \times T }{100}$

$\implies \rm \: 110 = \frac{10 \cancel{00} \times 5 \times T }{1 \cancel{00}}$

$\implies \rm \: 110 = 10 \times 5T$

$\implies \rm \: 110 = 50T$

$\implies \rm \: T = \frac{ \cancel{11} \cancel0}{ \cancel5 \cancel0}$

$\implies \rm \: \blue{ T = 2.2}$

Hence,

• The time is 2.2 years.