Question

Find the time taken by the 500 Watt Heater to raise the temperature of 50 kg of material of specific heat capacity 960 joule per kg per Kelvin from 18 degree Celsius to 30 degree Celsius assumed that all the heat supplied by heater is given to the material

Answer 1

Heya friend!!
Rajdeep here....

Given, Power P = 500W
m = 50kg
C (Specific heat capacity) = 960J/kgK
or 960J/kg°C
∆t (change in temperature) = 30 - 18 = 12°C

Now,
Heat supplied per second = heat absorbed by the .material

=> P × t = mC∆t
=> 500t = 50×960×12
=> t = 50×960×12/500
=> t = 576000/500
=> t = 1152 seconds.

Thanks!!