Question

find the time taken to transfer 3.2×10^6 electrons if net current flowing is 10A​

Answer 1

Answer:

Given:

No of electrons = 3.2 × 10^6 electrons.

Current = 10 A

To find:

Time taken

Calculation:

First we need to calculate the amount of charge passing through the conductor. We know that charge of each electron is 1.6 × 10^(-19) C

So total charge :

$charge = (1.6 \times {10}^{ - 19} ) \times (3.2 \times {10}^{6} )$

$= > charge = 5.12 \times {10}^{ - 13} C$

Now we know that , current is actually defined as the flow of charge :

$current = \dfrac{charge}{time}$

$= > time = \dfrac{charge}{current}$

$= > time = \dfrac{5.12 \times {10}^{ - 13} }{10}$

$= > time = 5.12 \times {10}^{ - 14} sec$

So final answer :

$\boxed{ \red{ \bold{ \sf{ \huge{time = 5.12 \times {10}^{ - 14} sec}}}}}$

Answer 2

$\tt{\huge{\pink{Hello!!! }}}$

$\tt{\blue{Formulae \:Used \::- }}$

$\tt{ \leadsto{ \purple{q = ne} }}......(1)$

$\tt{ \red{ \leadsto{q \: = it}}}$

Using these two relations,

t = 5.12 × 10^-14 Sec.