Question

.
Find the time taken when

(b) Distance = 1500 m, Speed = 18 km/hr
6
(c) Distance = 27 km, Speed = 45 km/hr​

Answer 1

Step-by-step explanation:

b) 18*5/18=5m/s

time =distance/speed

t=1500/5 =300sec

c) distance=27000m

speed=45*5/18=12.5m/s

t=27000/12.5=2160

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Answer 2

$\huge\bold{\color{aqua}{Solution :-}}$

$\bold{ \red{(b)}}$

$\bold{\green{Distance}=\pink{1500\:m}=\pink{1.5\:km}}$

$\bold{\green{Speed}=\pink{18\:km/hr}}$

$\bold{\purple{\text{We know that }}}$

$\quad\bold{\blue{Time \:Taken}=\orange{\frac{Distance}{Speed}}}$

$\Rightarrow\bold{Time \:Taken=\frac{1.5}{18}\:hr}$

$\Rightarrow\bold{Time \:Taken=\frac{1.5}{18}×60\:min}$

$\Rightarrow\bold{Time \:Taken=\frac{90}{18}\:min}$

$\Rightarrow\bold{Time \:Taken=\frac{\red{\cancel{\blue{90}}}^{\green{\:5}}}{\red{\cancel{\blue{18}}}}\:min}$

$\Rightarrow\bold{\green{\boxed{\blue{\bold{Time \:Taken}}=\pink{\bold{18\:min}}}}}$

$\bold{ \red{(c)}}$

$\bold{\green{Distance}=\pink{27\:m}}$

$\bold{\green{Speed}=\pink{45\:km/hr}}$

$\bold{\purple{\text{We know that }}}$

$\quad\bold{\blue{Time \:Taken}=\orange{\frac{Distance}{Speed}}}$

$\Rightarrow\bold{Time \:Taken=\frac{27}{45}\:hr}$

$\Rightarrow\bold{Time \:Taken=\frac{\red{\cancel{\blue{27}}}^{\green{\:3}}}{\red{\cancel{\blue{45}}}^{\green{\:5}}}\:hr}$

$\Rightarrow\bold{Time \:Taken=\frac{3}{5}×60\:min}$

$\Rightarrow\bold{Time \:Taken=\frac{180}{5}\:min}$

$\Rightarrow\bold{Time \:Taken=\frac{\red{\cancel{\blue{180}}}^{\green{\:36}}}{\red{\cancel{\blue{\:5}}}}\:min}$

$\Rightarrow\bold{\green{\boxed{\bold{\blue{Time \:Taken}=\pink{36\:min}}}}}$