Question

find the time using v
${v}^{2} \: - {u}^{2} \: = 2as$
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Answer 1

Answer:

HEY MATE!!!

Explanation:

First of all you have to know the other two equations of motions :

1. V=u+at

2. S=ut+1\2at2

*Now the derivation:

From the first equation we have :

:- at=v−u

:- t=v−u\a

*Now putting the value of t in the second equation of motion:

:- s=u(v−u\a)+1\2a(v−u\a)2

:- s=uv−u2\a+a(v2+u2–2vu)\2a2

:- s=uv−u2\a+(v2+u2+2vu)\2a

:- s=(2uv−2u2+v2+u2–2vu)\2a

:- 2as=v2−u2

:- v2=u2+2as

:- v2 = u2 + 2asv2=u2+2as

Proved

hope it helps

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