Find the time when ₹21000 gives an interest of ₹5040 at 6/per annum
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Answered by
7
Given , sum (p ) = ₹21000
rate = 6 % per annum ,
interest (S.I) = ₹5040
Find the time :
___________
Simple interest(S.I) = p × r × t / 100
5040 = 21000 × 6 × t / 100
t = 5040 /210 × 6
t = 504 / 126
t = 4 years
therefore ,
the sum ₹ 21000 will give an interest of ₹ 5040 at the rate of 6 % per annum in 4 years .
Answer : required time = 4 yrs
_______________________________
rate = 6 % per annum ,
interest (S.I) = ₹5040
Find the time :
___________
Simple interest(S.I) = p × r × t / 100
5040 = 21000 × 6 × t / 100
t = 5040 /210 × 6
t = 504 / 126
t = 4 years
therefore ,
the sum ₹ 21000 will give an interest of ₹ 5040 at the rate of 6 % per annum in 4 years .
Answer : required time = 4 yrs
_______________________________
Answered by
6
Find interest for 1 year:
Interest = 6% x ₹21000
Interest = 0.06 x 21000 = ₹1260
Find the number of years to earn ₹5040
1 year = ₹1260
Number of years needed = 5040 ÷ 1260 = 4
Answer: 4 years
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