Find the time when a body is thrown vertically up with an initial velocity of 60 metre per second and acceleration due to gravity is 10 metre per second square at the height of hundred metre
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Explanation:
s=ut-1/2gt^2
100=60×t-(1/2)×10×t×t
100=60t-5t^2
-5t^2+60t-100=0
t^2-12t+20=0
t^2-2t-10t+20=0
t(t-2)-10(t-2)=0
(t-2)(t-10)=0
time to reach the max height=2s or 10s
time to reach back to the starting point= 4s or 20s
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