Question

Find the time, when
(a) principal = 38500, rate = 6,25%, interest = 450.-​

Answer 1

➤ Correct Question :-

Find the time when,

Principle = 38500 ; Rate = 6.25% ; Interest = 450

➤ Given :-

Principle :- ₹ 38500

Rate :- 6.25 %

Simple Interest :- ₹ 450

➤ To Find :-

Time given for the given sum..............

➤ Formula required :-

${ \large \dashrightarrow \tt \orange{ \boxed{ \tt \gray{ \frac{SI \times 100}{P \times R} }}}}$

➤ Solution :-

Time :-

${ \tt \longrightarrow \dfrac{450 \times 100}{38500 \times 6.25} = \dfrac{450 \times 10000}{38500 \times 625} }$

${\tt \longrightarrow \dfrac{450 \times \cancel{10000}}{ \cancel{38500} \times 625} = \dfrac{450 \times 100}{385 \times 625} }$

${ \tt \longrightarrow \dfrac{ \cancel{450} \times 100}{385 \times \cancel{625}} = \dfrac{18 \times 100}{385 \times 25} }$

${ \tt \longrightarrow \dfrac{18 \times \cancel{100}}{ \cancel{385} \times 25} = \dfrac{18 \times 20}{77 \times 25} }$

${ \tt \longrightarrow \dfrac{18 \times \cancel{20}}{77 \times \cancel{25}} = \dfrac{18 \times 4}{77 \times 5} }$

${\longrightarrow \tt\cancel \dfrac{72}{385} = 0.18}$

$\Huge\therefore$The time taken in the following sum is 0.18 years.

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$\dashrightarrow$Some related formulas :-

Simple Interest :- $\boxed{\tt\dfrac{P \times R \times T}{100}}$

Principle :- $\boxed{\tt\dfrac{SI \times 100}{R \times T}}$

Rate of interest :- $\boxed{\tt\dfrac{SI \times 100}{P \times T}}$

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More to know..................

• Simple interest is the extra amount to be given when a person borrows money from a bank or a person. The person who takes money is a borrower. The person who gives money is a lender.
• Principle is the amount given at first from lender to borrower.
• Rate of interest is the extra amount to be given from borrower to lender, it is always written in percentage form.
• Time is given for borrower to return back the money with the interest given.