Question

Find the time when :
(i) rupees 1250 amounts to rupees1950 at 16% per annum ​

Answer 1

Answer:

time 2 years

1950=1250(116/100)✓n

2

Answer 2

Given :

• Principal = Rs. 1250
• Amount = Rs. 1950
• Rate = 16% per annum

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To Find :

• Time = ?

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Formula Used :

• ${\boxed{\pink{\bf{T = \dfrac{100 × SI}{P × R}}}}}$

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Solution :

Here's given that, Rs. 1250 amounts to Rs. 1950 at 16% per annum. As we know,

$\leadsto \: \sf{Amount = (principal + interest)}$

$\leadsto \: \sf{Rs. \: 1950 = Rs. \: 1250 + interest}$

$\leadsto \: \sf{Rs. \: 1950 - Rs. 1250 = interest}$

$\leadsto \: \purple{\sf{interest = Rs. \: 700}}$

Hence, simple interest (SI) is Rs 700.

Now, we have to substitute - simple interest (SI), Principal (P) and Rate (R) to find the time when rupees 1250 amounts to rupees 1950 at 16% per annum in the given formula :

$\tt{ \red\bigstar \: T = \dfrac{100 × SI}{P × R} \: \red\bigstar }$

Let's do it!!

$\mapsto \: \sf{T = \dfrac{ \cancel{100}^{ \: 2} × 700}{ \cancel{1250}_{ \: 25} × 16}}$

$\mapsto \: \sf{T = \dfrac{2 × \cancel{700}^{ \: 28} }{ \cancel{25}_{ \: 1} × 16} }$

$\mapsto \: \sf{T = \dfrac{ \cancel{2}^{ \: 1} × 28}{ \cancel{16}_{ \: 8} } }$

$\mapsto \: \sf{T = \dfrac{ \cancel{28}^{ \: 7} }{ \cancel{8}_{4} } }$

$\mapsto \: \sf{T = 1 \dfrac{3}{4} }$

$\mapsto \: \sf{T = 1 + \dfrac{3}{4} × 12}$

$\mapsto \: \sf{T = 1 \: year \: \& \: 9 \: months}$

Hence, the time when rupees 1250 amounts to rupees 1950 at 16% per annum is 1 year & 9 months.