Question

find the time when principal 1000rs si rs 350 r 7 %​

Answer 1

Given :

• Principal = 1000 rupees.
• S.I = 350 rupees.
• Rate = 7%.

To find :

• Time.

Solution :

$\bf \implies S.I = \dfrac{PTR}{100} \\ \\ \bf \implies 350 = \dfrac{1000 \times T \times 7\% }{100} \\ \\ \bf \implies 350 = \dfrac{10 \times T \times 7\% }{1} \\ \\ \bf \implies70T = 350 \\ \\ \bf \implies T = \frac{350}{70} \\ \\ \bf \implies T =5 \: years.$

Therefore, Time = 5 years.

Verification :-

$\bf \implies S.I = \dfrac{PTR}{100} \\ \\ \bf \implies350 = \frac{1000 \times 5 \times 7}{100} \\ \\ \bf \implies350 = \frac{10 \times 5 \times 7}{1} \\ \\ \bf \implies350 = \frac{350}{1} \\ \\ \bf \implies350 = 350 \\ \\ \bf LHS = RHS \\ \\ \bf Hence, Verified$

Answer 2

Answer:

$\Large\dag\large{\underline{\frak{\red{Given}}}}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}&\bf\:Given - \begin{cases} &\sf \star \: {Principal = Rs. 1000} \\ &\sf \star \: {Simple \: Interest=Rs.350} \\& \sf \star \: {Rate = 7 \% \: p.a} \end{cases}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

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$\Large\dag\large{\underline{\frak{\red{To \: Find }}}}$

$\begin{gathered}\begin{gathered}\begin{gathered}&\bf \:To \: find - \begin{cases} &\sf \star\:{Time } \end{cases}\end{gathered}\end{gathered}\end{gathered}$

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$\Large\dag\large{\underline{\frak{\red{Using \: formula \: to \: find \: Time}}}}$

$: \implies\bf{S.I} = \sf {\dfrac{P \times R \times T }{100}}$

$\begin{gathered}\small\begin{gathered}\begin{gathered}\begin{gathered}&\bf\:Where - \begin{cases} & \sf{S.I = Simple \: Interest} \\ & \sf{ P = Principal } \\ & \sf{R = Rate \: of \: Interest} \\& \sf{ T = Time} \end{cases}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

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$\Large \dag\large \underline\frak \red{Solution}$

$: \implies \bf{350} = \sf\dfrac{1000 \times T \times 7}{100} \\ \\:\implies \bf{350} = \sf \dfrac {\cancel{7000} \times T } {\cancel{100}} \\ \\ : \implies \bf350 = \sf {70 \times T} \\ \\ : \implies\bf{T }= \sf \cancel\frac{350}{70} \\ \\ \bf{T} = \sf 5 \: years \\ \\ \large\underline{\boxed{ \bf \pink{Time} = \sf \purple{5 \: years}}}$

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$\Large \dag\large \underline\frak \red{Verification}$

$: \implies \bf{350} = \sf\dfrac{1000 \times T \times 7}{100} \\ \\ \: \: \: \: \: \: :\implies \bf{350} = \sf\dfrac{1000 \times 5 \times 7}{100} \\ \\ : \implies \bf{350} = \sf \cancel\dfrac{35000}{100} \\ \\ : \implies \bf{350 = 350} \\ \\ \large\underline{\boxed{ \bf \purple{LHS} = \pink{RHS }}} \\ \sf{Hence \: Verified }$

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$\Large \dag\large \underline\frak \red{Therefore}$

• ↝ The Time Period is 5 years.