Question

find the time when principal is rupees 2000 and SI is rupees 330 and rate is 11% per annum

Answer 1

Heya,

According to the question,

Principal (P) = ₹2000

Simple interest (SI) = ₹330

Rate(R) = 11%

Time(T) = ?

SI = P×R×T/100

Therefore,

330 = 2000×11×T/100

T = 330/220

T = 1.5

So,

Time (T) = 1.5years

Hope this helps...:)