Question

Find the time when principles 52000 amount 6450 and rate 12℅ p.a

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Answer 1

$\bigstar\bold{\red{ \underline{\boxed{\bf{Correct\:Question:-}}}}}$

• Find the time when principles 5000 amount 6450 and rate 12℅ p.a.

$\bigstar\bold{\blue{ \underline{\boxed{\bf{Answer:-}}}}}$

• Time = 2 years 5 months.

${ \underline { \underline{ \texttt{ \pink{Given :-}}}}}$

• Amount = 6450
• Principle Amount =5000

${ \underline { \underline{ \texttt{ \red{To Find :-}}}}}$

• Time = ?

${ \underline { \underline{ \texttt{ \orange{Explaination :-}}}}}$

$\sf \: { \bigstar \: {Simple \: Interest}} = Amount - Principal Amount \\ \sf \: = 6450 - 5000 \\ \sf \: = 1450$

$\sf \: Simple \: Interest :-\: \\ \\ \longmapsto\sf \: SI = \dfrac{PRT}{100} \\ \\ \longmapsto\sf \: 1450 = \frac{5000 \times 12 \times T}{100} \\ \\ \longmapsto\sf \: 1450 \times 100 = 5000 \times 12 \times T \\ \\ \longmapsto\sf \: 60000 T=145000 \\ \\ {\blue{\longmapsto{\sf{ T= 2.416}}}}$

$\sf \: T = 2 \times 416667 \times 12 ; \\ \\ \therefore { \purple{ \underline{ \underline{\sf{Time = 2 \: years \: 5 \: months}}}}}$

Answer 2

$\sf{\huge{\bold{\orange{\bigstar{\boxed{\boxed{Question}}}}}}}$

• Find the time when principles 5000 amount 6450 and rate 12℅ p.a

$\sf{\huge{\bold{\orange{\bigstar{\boxed{\boxed{Solution}}}}}}}$

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

• Principle = Rs. 5000
• Amount = 6450
• rate = 12%

$\sf{\bold{\green{\underline{\underline{To\: find}}}}}$

• Time = ?????

$\sf{\bold{\pink{\underline{\underline{Explanatiom}}}}}$

$\sf{\bold{\red{\boxed{\boxed{Amount = principle + interest}}}}}$

$\sf\implies Amount = principle + interest$

$\sf\implies 6450 = 5000 + interest$

$\sf\implies interest = 6450 - 5000$

$\sf\implies interest = Rs.1450$

$\sf{\bold{\red{\boxed{\boxed{ Interest = \dfrac {prt}{100}}}}}}$

$\sf\implies { 1450 =\dfrac{ 5000 \times 12 \times t }{100}}$

$\sf\implies {1450\times 100 = 5000 \times 12 \times t }$

$\sf\implies \dfrac{1450\times \cancel{100}}{50\cancel{00}\times 12} = t$

$\sf\implies \dfrac{145\cancel{0}}{60\cancel{0}}= t$

$\sf\implies \dfrac{\cancel{145}}{\cancel{60}}= t$

$\sf\implies \dfrac{29}{12}$

• converting into years and months

$\sf\implies 2 \dfrac{5}{12}$

$\sf\implies 2 years 5months$

$\sf{\bold{\pink{\boxed{\boxed{ \dag 2years\:5months }}}}}$

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