find the time when Rs. 21000 gives an interest of Rs. 5040 at 6% per annual
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let principal be p, time be t, interest be SI, and rate be r..
time = (SI *100)/rate* principal
time=5040*100/6*21000 =4
so the time is 4years.. is answer.
thank you for this question..
havea nice day...
I hope it may help you..
time = (SI *100)/rate* principal
time=5040*100/6*21000 =4
so the time is 4years.. is answer.
thank you for this question..
havea nice day...
I hope it may help you..
Answered by
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Hey there! ☺☻☺
![Principal = P = Rs. 21000\\Rate = R = 6\%\\Time = T = ?\\S.I = Rs. 5040\\\\We \ know,\\S.I = \frac{P\times R\times T}{100}\\\\5040=\frac{21000 \times 6 \times T}{100}\\\\\frac{5040\times 100}{21000\times 6} = T\\\\T = \frac{504}{126}\\\\\boxed{\boxed{\bold{T = 4 \ years}}} Principal = P = Rs. 21000\\Rate = R = 6\%\\Time = T = ?\\S.I = Rs. 5040\\\\We \ know,\\S.I = \frac{P\times R\times T}{100}\\\\5040=\frac{21000 \times 6 \times T}{100}\\\\\frac{5040\times 100}{21000\times 6} = T\\\\T = \frac{504}{126}\\\\\boxed{\boxed{\bold{T = 4 \ years}}}](https://tex.z-dn.net/?f=Principal+%3D+P+%3D+Rs.+21000%5C%5CRate+%3D+R+%3D+6%5C%25%5C%5CTime+%3D+T+%3D+%3F%5C%5CS.I+%3D+Rs.+5040%5C%5C%5C%5CWe+%5C+know%2C%5C%5CS.I+%3D+%5Cfrac%7BP%5Ctimes+R%5Ctimes+T%7D%7B100%7D%5C%5C%5C%5C5040%3D%5Cfrac%7B21000+%5Ctimes+6+%5Ctimes+T%7D%7B100%7D%5C%5C%5C%5C%5Cfrac%7B5040%5Ctimes+100%7D%7B21000%5Ctimes+6%7D+%3D+T%5C%5C%5C%5CT+%3D+%5Cfrac%7B504%7D%7B126%7D%5C%5C%5C%5C%5Cboxed%7B%5Cboxed%7B%5Cbold%7BT+%3D+4+%5C+years%7D%7D%7D)
Hope It Helps You! ☺☻☺
Hope It Helps You! ☺☻☺
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