Question

find the time when S.I=RS.1575 P=Rs.5250
Rate=10%​

Answer 1

Given:

Principal = Rs. 5,250

Rate% = 10%

Interest = Rs. 1,575

To find:

Time period

$s.i. = \frac{prt}{100}$

$1575 = \frac{5250 \times 10 \times t}{100}$

$1575 = 525t$

$\frac{1575}{525} = t$

3 years = T

Answer:

Therefore the time period for which the principal was borrowed at 10% rate is 3 years.

Answer 2

Solution

Given ,

• p ( principal ) = ₹5250
• R ( rate per annum ) = 10%
• simple interest = 1,575

To find ,

• we have to find here the time period .

we know that ,

Simple interest = prt/100

• Note :- here P refers to principal are first to rate per annum t refers to time

now putting the value in the equation we get ;

$= > 1575 = \frac{5250 \times 10 \times t}{100}$

$= > 1575 = 525 \times t$

$= >t = \frac{1575}{525}$

$\bold{ = > t = 3yrs}$

The time period is three years