Question

Find the time when simple interest on rs 2500at 4% per annum is rs 200.

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Answer 1

Answer:

=200=$\frac{2500*4*T}{100}$

=200=25*4*T

=200=100*T

=T=$\frac{200}{100}$

=T=2years

∴ Time= 2years.

Explanation:

Hope it will help you...

Answer 2

Answer:

The time will be of 2 years.

Step-by-step explanation:

In context to the question asked,

We have to find the time,

As per data given in the question,

We have,

Simple Interest ( S. I ) = Rs.$200$

Principal ( P ) = Rs.$2500$

Rate ( R ) = $4$%p.a.

As we know that, for calculating the required time:

The formula to be used:

$=> Time=\frac{S.I \times 10 0 }{P \times R }$

Substituting the given values:

$=> Time=\frac{200 \times 10 0 }{2500\times 4 }$

=> Time = 2 years

Hence, the required time is 2 years.